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600积分
本帖最后由 6688 于 2017-1-18 16:45 编辑
前几天有求PHP代码怎么写,但提交内容POST没有变化(我不会PHP,补充这个也行),现在求JS版本的,谢谢。
<?php echo $str;?> 就行了
- <?php
- $arr1=array("1","2","3","4","5","6","7","8","9","0");
- $arr2=array("一","二","三","四","五","六","七","八","九","零");
- function str_rep($a,$b,$str)
- {
- $res=str_replace($a, $b, $str);
- return $res;
- }
- print_r(str_rep($arr1,$arr2,$_POST['str']));
- ?>
- <!DOCTYPE html>
- <html lang="en">
- <head>
- <meta charset="UTF-8">
- <title>demo</title>
- <meta http-equiv="Content-Type" content="text/html; charset=utf-8"></head>
- <body>
- <form action="" method="post">
- <p><input type="text" name="str"></p>
- <p><button type="submit">submit</button></p>
- </form>
- </body>
- </html>
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print是输出到浏览器,没有改变参数的值,你需要把写入数据库的参数重新赋值
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